Free · Worked example · 12 problems · Answer key · US Letter
How to do it
When the curve is above the x-axis, the area is the definite integral from a to b.
the area under y=2x2+x+4 from x=1 to x=3:388 area =∫13(2x2+x+4)dxthe curve is above the x-axis here F(x)=32x3+2x2+4x (269)−(631)=388 Example problems
- the area under y=3x2−2x+9 from x=2 to x=4:
- the area under y=3x2+4x+2 from x=1 to x=5:
- the area under y=2x2−x+9 from x=0 to x=4:
- the area under y=3x2+3 from x=1 to x=4:
Integrals
- Antiderivatives with the power rule
- Integrals of 1/x, eˣ, sin and cos
- Integration by u-substitution
- Evaluating definite integrals
- Area under a curve
- Area between two curves
- Average value of a function