Free · Worked example · 18 problems · Answer key · US Letter
How to do it
Sₙ = a₁(rⁿ − 1) ÷ (r − 1).
the first 5 terms of 3,9,27,...:sum=363 a1=3,r=3,n=5 3−13(35−1)=23(243−1)=363Sₙ = a₁(rⁿ − 1) ÷ (r − 1) Example problems
- the first 5 terms of 1,−2,4,...:sum=
- the first 6 terms of 3,6,12,...:sum=
- the first 6 terms of 2,−4,8,...:sum=
- the first 4 terms of 5,15,45,...:sum=
Sequences and series
- Arithmetic sequences
- Geometric sequences
- Writing the formula for a sequence
- Sigma notation
- Arithmetic series
- Geometric series
- Infinite geometric series
- Combinations (nCk)
- The binomial theorem